2x^2-8x+23=0

Solution for 2x^2-8x+23=0 equation:

Simplifying
2x2 + -8x + 23 = 0

Reorder the terms:
23 + -8x + 2x2 = 0

Solving
23 + -8x + 2x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
11.5 + -4x + x2 = 0

Move the constant term to the right:

Add '-11.5' to each side of the equation.
11.5 + -4x + -11.5 + x2 = 0 + -11.5

Reorder the terms:
11.5 + -11.5 + -4x + x2 = 0 + -11.5

Combine like terms: 11.5 + -11.5 = 0.0
0.0 + -4x + x2 = 0 + -11.5
-4x + x2 = 0 + -11.5

Combine like terms: 0 + -11.5 = -11.5
-4x + x2 = -11.5

The x term is -4x.  Take half its coefficient (-2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
-4x + 4 + x2 = -11.5 + 4

Reorder the terms:
4 + -4x + x2 = -11.5 + 4

Combine like terms: -11.5 + 4 = -7.5
4 + -4x + x2 = -7.5

Factor a perfect square on the left side:
(x + -2)(x + -2) = -7.5

Can't calculate square root of the right side.

The solution to this equation could not be determined.